I believe the answer is:
11 + 6(n-1)
Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence.
The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
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To find the nth term in this sequence, we first need to determine the pattern. The difference between each term is 6 (17-11=6, 23-17=6, 29-23=6), indicating an arithmetic sequence. The formula for the nth term in an arithmetic sequence is Tn = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. Plugging in the values from the sequence, we get Tn = 11 + (n-1)6 = 11 + 6n - 6 = 6n + 5. Therefore, the nth term in this sequence is 6n + 5.
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
The answer depends on the context. It could refer to the nth term in a sequence of numbers: T1, T2, ...
four hundred and nity six
There is no such formula. Rectangular numbers are composite numbers and there is no known formula that will generate either composite numbers or prime numbers.