There are the square numbers 1² = 1, 2² = 4, 3² = 9, etc; thus the nth term is n squared:
t(n) = n²
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
square of (n x 2)
(n+1)^2 Please tell me you know what that means.
The nth term is (36 - 4n)
n^2 + 2n + 1
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
square of (n x 2)
(n+1)^2 Please tell me you know what that means.
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.
The nth term is (36 - 4n)
n^2 + 2n + 1
72/2n
The sequence given consists of the squares of the natural numbers: (1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2, 8^2, 9^2). To find the nth term of the sequence, you can use the formula (n^2), where (n) is the position in the sequence. Therefore, the nth term is (n^2).
The given sequence is 12, 20, 28, 36, 44. To find the nth term, observe that the difference between consecutive terms is consistently 8. Therefore, we can express the nth term as ( a_n = 12 + 8(n - 1) ), which simplifies to ( a_n = 8n + 4 ). Thus, the nth term of the sequence is ( a_n = 8n + 4 ).
You must mean what is the next number in the series, not the 'nth', which is undefined. The next number is 58.
For {12, 15, 18} each term is the previous term plus 3; a general formula for the nth term is given by t(n) = 3n + 9. For {12, 24, 36} each term is the previous term plus 12; a general formula for the nth term is given by t(n) = 12n.
-16