t(n) = 29 - 7n where n = 1, 2, 3, ...
76
Well, well, well, look at you trying to be all smart with your math question. The nth term of that sequence is n^2 + 4. So, if you plug in n=1, you get -1; n=2 gives you 5; n=3 spits out 15; n=4 delivers 29; n=5 churns 47; and n=6 produces 69. Voilà!
29. To find range, you subtract the lowest term, from the largest term. 39-10=29
Un = 29 - 9n
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
t(n) = 29 - 7n where n = 1, 2, 3, ...
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
76
nth term = 5 +8n
Well, darling, it looks like we have a arithmetic sequence going on here. The common difference between each term is 7, so to find the nth term, you can use the formula a_n = a_1 + (n-1)d. In this case, a_1 is 1 and d is 7, so the nth term would be 1 + (n-1)7, which simplifies to 7n - 6. Voila!
9n+2
2n +29
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1