t(n) = 29 - 7n where n = 1, 2, 3, ...
76
Well, well, well, look at you trying to be all smart with your math question. The nth term of that sequence is n^2 + 4. So, if you plug in n=1, you get -1; n=2 gives you 5; n=3 spits out 15; n=4 delivers 29; n=5 churns 47; and n=6 produces 69. Voilà!
29. To find range, you subtract the lowest term, from the largest term. 39-10=29
Un = 29 - 9n
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
t(n) = 29 - 7n where n = 1, 2, 3, ...
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
76
nth term = 5 +8n
Well, darling, it looks like we have a arithmetic sequence going on here. The common difference between each term is 7, so to find the nth term, you can use the formula a_n = a_1 + (n-1)d. In this case, a_1 is 1 and d is 7, so the nth term would be 1 + (n-1)7, which simplifies to 7n - 6. Voila!
9n+2
2n +29
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1