The sequence 8, 15, 22, 29, 36 is an arithmetic sequence where each term increases by 7. The first term (a) is 8, and the common difference (d) is 7. The nth term can be expressed using the formula: ( a_n = a + (n-1) \cdot d ). Therefore, the nth term is ( a_n = 8 + (n-1) \cdot 7 = 7n + 1 ).
t(n) = 29 - 7n where n = 1, 2, 3, ...
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
To find the nth term of the sequence -1, 5, 15, 29, 47, 69, we first observe the differences between consecutive terms: 6, 10, 14, 18, 22. The second differences are constant at 4, indicating a quadratic relationship. The general form for the nth term can be expressed as ( an^2 + bn + c ). By solving the system of equations formed by substituting n=1, 2, and 3, we find the nth term is ( 2n^2 + 2n - 3 ).
76
Well, well, well, look at you trying to be all smart with your math question. The nth term of that sequence is n^2 + 4. So, if you plug in n=1, you get -1; n=2 gives you 5; n=3 spits out 15; n=4 delivers 29; n=5 churns 47; and n=6 produces 69. Voilà!
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
t(n) = 29 - 7n where n = 1, 2, 3, ...
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
76
Oh, dude, okay, so the nth term of 1, 8, 15, 22, 29 is basically adding 7 each time. So, if you want the nth term, you just take the first term, which is 1, and then add 7 times n-1. Like, it's that simple. Math can be chill sometimes, you know?
nth term = 5 +8n
2n +29
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1