n^2 + 2n + 1
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
(n+1)^2 Please tell me you know what that means.
square of (n x 2)
The nth term is (36 - 4n)
72/2n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
(n+1)^2 Please tell me you know what that means.
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.
square of (n x 2)
The nth term is (36 - 4n)
The sequence given consists of the squares of the natural numbers: (1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2, 8^2, 9^2). To find the nth term of the sequence, you can use the formula (n^2), where (n) is the position in the sequence. Therefore, the nth term is (n^2).
72/2n
The given sequence is 12, 20, 28, 36, 44. To find the nth term, observe that the difference between consecutive terms is consistently 8. Therefore, we can express the nth term as ( a_n = 12 + 8(n - 1) ), which simplifies to ( a_n = 8n + 4 ). Thus, the nth term of the sequence is ( a_n = 8n + 4 ).
There are the square numbers 1² = 1, 2² = 4, 3² = 9, etc; thus the nth term is n squared: t(n) = n²
The sequence 18, 27, 36, 45, 54 is an arithmetic sequence where each term increases by 9. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term (18) and ( d ) is the common difference (9). Thus, the nth term is ( a_n = 18 + (n-1) \times 9 = 9n + 9 ).
The sequence 8, 15, 22, 29, 36 is an arithmetic sequence where each term increases by 7. The first term (a) is 8, and the common difference (d) is 7. The nth term can be expressed using the formula: ( a_n = a + (n-1) \cdot d ). Therefore, the nth term is ( a_n = 8 + (n-1) \cdot 7 = 7n + 1 ).
You must mean what is the next number in the series, not the 'nth', which is undefined. The next number is 58.