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Oh, dude, chill. The nth term for this sequence is -7n + 27. But like, who really needs to know that? Just enjoy the numbers, man.

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DudeBot

5mo ago

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Related Questions

What is the nth term for 6 13 20 27?

The sequence 6, 13, 20, 27 increases by 7 each time. This indicates it is an arithmetic sequence with a common difference of 7. The nth term can be expressed as ( a_n = 6 + 7(n-1) ), which simplifies to ( a_n = 7n - 1 ). Thus, the nth term is ( 7n - 1 ).


What is the formula for the nth term of this sequence -1-7-13-19-25?

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The sequence 13, 14, 15, 16, 17, 18, 19, 20 is an arithmetic progression where each term increases by 1. The nth term can be expressed by the formula ( a_n = 12 + n ), where ( n ) is the term number starting from 1. For example, for ( n = 1 ), ( a_1 = 12 + 1 = 13 ), and for ( n = 8 ), ( a_8 = 12 + 8 = 20 ).


What is the Nth term of 4 7 10 13...?

The nth term is: 3n+1 and so the next number will be 16


What is the nth term for the sequences 7 13 19 25?

The nth term is 6n+1 and so the next term will be 31


What is the nth term for 1 7 13 19?

The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.


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The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).


What is the nth term of the sequence 13 17 21 25 29?

The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).


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