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What is the nth term of 2 10 26 50 82?
t(n) = 4n2 - 4n + 2
What is the nth term of 14 23 32 and 41?
It is: 9n+5 and so the next term is 50
What is the nth term for 14 23 32 41 50?
5+9n
What is the nth term 2 8 18 32 50?
There are infinitely many possible answers, but the simplest is Un = 2n2
A sequence begins 2 8 18 32 50 What is its nth term?
the sequence is Un=2n2
What is the nth term of 2 10 26 50 82?
t(n) = 4n2 - 4n + 2
What is an example of a nth term?
Nth term With the nth term you substitute the n for the term number (e.g. 50) so the 50th term in 2n+3 would be 2x50+3=103
What is 26 percent off of 50?
26% of 50 is 13 and so 50-13 = 37
What is the nth term of 14 23 32 and 41?
It is: 9n+5 and so the next term is 50
Find the percent decrease from 50 to 37?
double both so 50 to 37 = 100 to 74 then 100 - 74 = 26 Answer: 26% decrease
What is the nth term of 50 49 46 41 34?
-n2+2n+49
What is the 9th term in the quadratic sequence 2 5 10 17 26?
To find the nth term in a quadratic sequence, we first need to determine the pattern. In this case, the difference between consecutive terms is increasing by 3, 5, 7, 9, and so on. This indicates a quadratic sequence. To find the 9th term, we need to use the formula for the nth term of a quadratic sequence, which is given by: Tn = an^2 + bn + c. By plugging in n=9 and solving for the 9th term, we can find that the 9th term in this quadratic sequence is 74.
What is the percent decrease from 50 to 37?
26 percent.
What is the nth term of -2-8-18-32-50?
The sequence given is -2, -8, -18, -32, -50. To find the nth term, we first observe the differences between consecutive terms: -6, -10, -14, -18, which show that the second differences are constant at -4. This indicates that the nth term can be expressed as a quadratic function. By fitting the sequence to the form ( a_n = An^2 + Bn + C ), we find that the nth term is ( a_n = -2n^2 + 2n - 2 ).
What is the nth term for 14 23 32 41 50?
5+9n
What is the nth term for the sequence -2 -8 -18 -32 -50?
To find the nth term of the sequence -2, -8, -18, -32, -50, we first observe the differences between consecutive terms: -6, -10, -14, -18. The second differences (which are constant at -4) suggest that the nth term can be represented by a quadratic function. The general form is ( a_n = An^2 + Bn + C ). Solving for coefficients A, B, and C using the first few terms gives the nth term as ( a_n = -2n^2 + n ).
What is the 50 term for 2 7 12 17?
The sequence goes up by 5 each time; the first term is two. So the nth term is 2 + 5n. n=50 => 2+50*5 = 252.
