To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence does not appear to follow a simple arithmetic or geometric progression. Therefore, it is likely following a pattern involving squares or cubes of numbers. By examining the differences between consecutive terms, we can deduce the pattern and determine the nth term. In this sequence, the differences between consecutive terms are 9, 15, 21, which are not constant. This suggests a more complex pattern, possibly involving squares or cubes of numbers.
+9
t(n) = n2 + 5n - 1
7n
2n^2-1
The next number in the sequence is a multiple of the number times seven, so the nth term would be 7n . 71 = 7 72 = 49 73 = 343 74 = 2,401 75 = 16,807 76 = 117,649 etc.
+9
t(n) = n2 + 5n - 1
-n2+2n+49
7n
2n^2-1
(Term)n = 59 - 2n
There are infinitely many possible answers. the simplest polynomial is Un = -n4 + 12n3 - 47n2 + 78n - 41
To find the nth term of a sequence, we first need to determine the pattern or rule that governs the sequence. In this case, the sequence appears to be increasing by adding consecutive odd numbers: 3, 6, 9, 12, and so on. Therefore, the nth term formula for this sequence is Tn = 3n^2 + n. So, the nth term for the sequence 4, 7, 13, 22, 34 is Tn = 3n^2 + n.
13/49 is in its lowest terms
The next number in the sequence is a multiple of the number times seven, so the nth term would be 7n . 71 = 7 72 = 49 73 = 343 74 = 2,401 75 = 16,807 76 = 117,649 etc.
fsedaz sd
It is 2849/1.