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To find the nth term in this sequence, we first need to determine the pattern. The differences between consecutive terms are 5, 7, 9, and 11 respectively. These differences are increasing by 2 each time. This indicates that the sequence is following a quadratic pattern. The nth term for this sequence can be found using the formula for the nth term of a quadratic sequence, which is Tn = an^2 + bn + c.
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What is the formula for the nth Term of these sequences 13 21 29 37 45 ...?
nth term = 5 +8n
What is the nth term formula for the sequence 13 29 25 31 37?
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
What is the nth term for 5 11 17 23 29?
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
What is the nth term for 5 8 13 20 29 40?
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
What is the nth term of the sequence -4 4 12 20 29?
The nth term of the sequence -4 4 12 20 29 is 8n+12 because each time the sequence is adding 8 which is where the 8n comes from. Then you take 8 away from -4 and because a - and - equal a + the answer is 12. Which is where the 12 comes from. Hope I helped.
