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The nth term is -7n+29 and so the next term will be -6

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It is 29 - 7n.

Q: What is the nth term of the arithmetic sequence 22 15 8 1 ...?

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It is: nth term = 29-7n

The nth term is 4n-1 and so the next term will be 19

Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.

According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.The simplest rule is un = 18 - 3n

The nth term is: 2n+7 and so the next number will be 19

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The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.

The nth term in this sequence is 4n + 3.

It is: nth term = 29-7n

The nth term is 4n-1 and so the next term will be 19

Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.

It is an Arithmetic Progression with a constant difference of 11 and first term 15.

This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.

The next term is: 15+4 = 19 The nth term is: 4n-5

after -9 it is -15 then -21, -27 and the ninth is -36

There are two ways to say the general rule. They both mean exactlythe same thing, and they both generate the same sequence:1). Starting with 15, each new term is 3 less than the one before it.2). The nth term of the sequence is [ 18 - 3n ] or [ 3 times (6 - n) ].

t(n) = 3n2 + n + 1

The nth term is: 5n