[ 6n + 8 ] is.
t(n) = n2 + n + 8
The nth term of the sequence is (n + 1)2 + 2.
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
[ 6n + 8 ] is.
t(n) = n2 + n + 8
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term of the sequence is (n + 1)2 + 2.
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
29.5263
If the term number is n, then the nth term is 10(n-1) +8.
38
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.