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We note that there are a difference of '9' between terms . Hence '9n'
Next find the constant 'c'
1st term ; 9(1) + c = 20 => c = 11
2 nd term ; 9(2) + c = 29 => c = 11
nth term is 9n + 11
e.g.
7th term is 9(7) + 11 = 63 + 11 = 74
What else can I help you with?
What is the nth term of 14 20 26 32 38?
[ 6n + 8 ] is.
What is the nth term for 6 11 18 27 38?
The nth term of the sequence is (n + 1)2 + 2.
What is the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the position to term rule of 8 18 28 38?
If the term number is n, then the nth term is 10(n-1) +8.
What is the nth term of 14 20 26 32 38?
[ 6n + 8 ] is.
What is the nth term for the sequence 10 17 24 31 38?
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
What is the nth term for 6 11 18 27 38?
The nth term of the sequence is (n + 1)2 + 2.
What is the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term for the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term if the sequence goes 18 23 28 33 38?
58
What is 1122 divided by 38?
29.5263
What is the position to term rule of 8 18 28 38?
If the term number is n, then the nth term is 10(n-1) +8.
What is the nth term rule of 11 20 29 38 47?
There are infinitely many possible answers. Given ANY number, it is always possible to find a polynomial of order 5 [at most] that can be used as the nth term rule for the given five number and the additional sixth. There are also non-polynomial solutions. Each different sixth number will result in a different polynomial and, since there are infinitely many sixth numbers, there are infinitely many answers to the question. Having said that, the simplest polynomial solution is Un = 9n - 2
What is 29-9 equals?
38
What is the nth term of 3 6 11 18 27?
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
