The sequence has a difference of 10, so the nth term starts with 10n.
Then to get to -8 from 10 you need to subtract 18.
So the nth term is 10n - 18.
5n+2
The nth term is (2n - 12).
t(n) = (5n3 - 30n2 + 85n - 48)/6 , n = 1, 2, 3, ...
12 - 5(n-1)
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
If you meant: 2 12 22 32 then the nth term = 10n-8
The nth term is 5n-3 and so the next term will be 22
5n - 3
5
5n+2
tn=5n-3
The nth term is (2n - 12).
It is: nth term = 7n-9
t(n) = (5n3 - 30n2 + 85n - 48)/6 , n = 1, 2, 3, ...
The nth term is 22n and so the next number will be 5*22 = 110
12 - 5(n-1)
The given sequence is -2, 1, 6, 13, 22, 33. To find the nth term, we observe that the differences between consecutive terms are increasing by 2 (3, 5, 7, 9). This indicates a quadratic pattern, and the nth term can be expressed as ( a_n = n^2 + n - 2 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 2 ).