Any number that you choose can be the nth number. It is easy to find a rule based on a polynomial of order 4 such that the first four numbers are as listed in the question followed by the chosen number in the nth position (n>4). There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
A solution, based on a polynomial of order 2, is
U(n) = n^2 - 1.
0,3,8,15,24,27,32,41
The nth term in this sequence is 4n + 3.
The nth term is 18 -3n and so the next term will be 3
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
Each term after the first is found by multiplying the previous term by 5. This idea can expressed as follows: a0 = 3 an = 5an-1 for n > 0. You can solve this recurrence to get the closed form , an=(3)5n , n >= 0,
0,3,8,15,24,27,32,41
The nth term in this sequence is 4n + 3.
If you mean: 15 11 7 3 then the nth term is 19-4n
The nth term is 18 -3n and so the next term will be 3
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
n-9+3
n - 1
after -9 it is -15 then -21, -27 and the ninth is -36
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The nth term is: 5-2n