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Any number that you choose can be the nth number. It is easy to find a rule based on a polynomial of order 4 such that the first four numbers are as listed in the question followed by the chosen number in the nth position (n>4). There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
A solution, based on a polynomial of order 2, is
U(n) = n^2 - 1.
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What is the nth term for 7 11 15 19?
The nth term in this sequence is 4n + 3.
What is the nth term of 15 12 9 6.?
The nth term is 18 -3n and so the next term will be 3
What is the nth term for 3 7 11 15?
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
What is the nth term if the sequence goes 3 15 75 375 1875?
Each term after the first is found by multiplying the previous term by 5. This idea can expressed as follows: a0 = 3 an = 5an-1 for n > 0. You can solve this recurrence to get the closed form , an=(3)5n , n >= 0,
What is the nth term for 3 5 7 9 11 13 15?
2n + 1
