Double it minus the previous number.
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...
If you mean: 15 11 7 3 then the nth term is 19-4n
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
The nth term in this sequence is 4n + 3.
The nth term is 4n-1 and so the next term will be 19
The nth term of the sequence is 2n + 1.
Double it minus the previous number.
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
9
tn = n2 - n + 3It is 75359152333455975
is 219 in the sequence of 4n-3
The nth term is 2n+5 and so the next number is 17
12 - 5(n-1)
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1