Double it minus the previous number.
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...
If you mean: 15 11 7 3 then the nth term is 19-4n
The nth term in this sequence is 4n + 3.
The nth term is 4n-1 and so the next term will be 19
The nth term of the sequence is 2n + 1.
Double it minus the previous number.
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
12 - 5(n-1)
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
The nth term is 2n+5 and so the next number is 17
The nth term is 5n-3 and so the next term will be 22
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.