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What is the the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is nth term for sequence 25 23 21 19 17?
It is: 27-2n
What is the nth term of 3 8 13 18 23?
Un = 5n - 2
What is the first 5 terms of the sequence with nth term 6n-1?
5, 11, 17, 23, 29
Nth term of the sequence 20 17 14 11 8?
This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.=================================The 'N'th term is: [ 23 - 3N ].
What is the nth term if the sequence goes 18 23 28 33 38?
58
What is the the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term for the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term in this sequence 18 23 28 33 38?
All you have to do is add 5 each time(x+5) It's 43
What is nth term for sequence 25 23 21 19 17?
It is: 27-2n
What is the nth term rule of the quadratic sequence 7 14 23 34 47 62 79 . . .?
It is T(n) = n2 + 4*n + 2.
What is the nth term for this sequence 3 5 9 15 23?
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
What is the nth term of 3 8 13 18 23?
Un = 5n - 2
What is the nth term of this sequence 18 23 28 33 38?
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
What is the nth term for 8 13 18 23?
It is: 5n+3 and so the next term is 28
What is the first 5 terms of the sequence with nth term 6n-1?
5, 11, 17, 23, 29
Find the nth term 11,17,23,29?
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
