Q: What is the the nth term of the sequence 18 23 28 33 38?

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The 'n'th term is [ 13 + 5n ].

It is: 27-2n

Un = 5n - 2

5, 11, 17, 23, 29

the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)

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58

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

All you have to do is add 5 each time(x+5) It's 43

It is: 27-2n

It is T(n) = n2 + 4*n + 2.

Un = 5n - 2

18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.

It is: 5n+3 and so the next term is 28

tn = n2 - n + 3It is 75359152333455975

5, 11, 17, 23, 29

the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)