kpihip'oih'oihyilgkutfgikrfi7kr67tr76
nth term = 5 +8n
15(1)
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
5n+1
t(n) = 28-3n where n = 1,2,3,...
nth term = 5 +8n
15(1)
1. -52. 103. -154. 205. -256. 307. -358. 409. -45
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
28
5n+1
t(n) = 28-3n where n = 1,2,3,...
3n^2 - n + 1
Yes, the fractions 15/28 and 45/84 are equivalent, as 45/84 reduces to 15/28.
To find the nth term of the sequence 3, 11, 25, 45, we first look for a pattern in the differences between the terms. The first differences are 8, 14, and 20, and the second differences are 6, 6, indicating that the sequence is quadratic. We can express the nth term as ( a_n = An^2 + Bn + C ). Solving for A, B, and C using the given terms, we find the nth term is ( a_n = 3n^2 - 3n + 3 ).
5/9 = 25/45 but not to 15/28