To find the nth term of a sequence, we need to identify the pattern or rule that governs the sequence. In this case, the sequence 5, 20, 45, 80 appears to be increasing by multiples of consecutive odd numbers. The differences between the terms are 15, 25, and 35, which are consecutive odd numbers 5, 3, and 7. Therefore, the nth term can be represented by the formula n^2 + 4, where n is the position of the term in the sequence.
{5, 20, 45, 80, 125} = 5{1, 4, 9, 16, 25} = 5{1², 2², 3², 4², 5²} → U{n} = 5n²
15(1)
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
nth term = 5 +8n
To find the nth term of a sequence, we first need to identify the pattern. In this case, the differences between consecutive terms are 9, 13, 17, and 21. These differences do not form a simple arithmetic progression, so the sequence likely involves a quadratic equation. By analyzing the pattern further, we can determine the general formula for the nth term.
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
{5, 20, 45, 80, 125} = 5{1, 4, 9, 16, 25} = 5{1², 2², 3², 4², 5²} → U{n} = 5n²
15(1)
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
nth term = 5 +8n
There are infinitely many possible solutions to such a question. The simplest quadratic is Un = 4n2 + 9
1. -52. 103. -154. 205. -256. 307. -358. 409. -45
tn = n2 + 9, n = 1,2,3,...
5n+1
3n^2 - n + 1
To find the nth term of a sequence, we first need to identify the pattern. In this case, the differences between consecutive terms are 9, 13, 17, and 21. These differences do not form a simple arithmetic progression, so the sequence likely involves a quadratic equation. By analyzing the pattern further, we can determine the general formula for the nth term.
t(n) = 28-3n where n = 1,2,3,...