To find the nth term of a sequence, we need to identify the pattern or rule that governs the sequence. In this case, the sequence 5, 20, 45, 80 appears to be increasing by multiples of consecutive odd numbers. The differences between the terms are 15, 25, and 35, which are consecutive odd numbers 5, 3, and 7. Therefore, the nth term can be represented by the formula n^2 + 4, where n is the position of the term in the sequence.
{5, 20, 45, 80, 125} = 5{1, 4, 9, 16, 25} = 5{1², 2², 3², 4², 5²} → U{n} = 5n²
t(n) = 28-3n where n = 1,2,3,...
15(1)
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
nth term = 5 +8n
{5, 20, 45, 80, 125} = 5{1, 4, 9, 16, 25} = 5{1², 2², 3², 4², 5²} → U{n} = 5n²
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
t(n) = 28-3n where n = 1,2,3,...
15(1)
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
nth term = 5 +8n
There are infinitely many possible solutions to such a question. The simplest quadratic is Un = 4n2 + 9
1. -52. 103. -154. 205. -256. 307. -358. 409. -45
tn = n2 + 9, n = 1,2,3,...
Oh, what a lovely sequence you have there! To find the pattern, let's look at the differences between the numbers: 9, 13, 17, 21. Do you see how the differences are increasing by 4 each time? That means the nth term is found by adding the square of n to the previous term. Happy math-ing, my friend!
5n+1
3n^2 - n + 1