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The sequence given is an arithmetic sequence with a common difference of 10 between each term. To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference. In this case, the first term a_1 is 15, the common difference d is 10, so the nth term a_n = 15 + (n-1) * 10 = 15 + 10n - 10 = 10n + 5.

Q: What is the nth term of the sequence 15 25 35 45 55?

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The nth term is: 5n

The nth term is: 5-6n

n2

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It is: 27-2n

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The nth term is: 5n

The nth term is: 5-6n

The nth term is 25-4n and so the next term will be 5

n2

It is 4n+5 and so the next term will be 25

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Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.

It is: 27-2n

The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.

The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.

Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}

Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2