The sequence given is an arithmetic sequence with a common difference of 10 between each term. To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference. In this case, the first term a_1 is 15, the common difference d is 10, so the nth term a_n = 15 + (n-1) * 10 = 15 + 10n - 10 = 10n + 5.
The nth term is: 5n
The nth term is: 5-6n
n2
Give me a answer
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
The nth term is: 5n
The nth term is: 5-6n
The nth term is 25-4n and so the next term will be 5
n2
Give me a answer
It is 4n+5 and so the next term will be 25
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
It is: 27-2n
t(n) = 28-3n where n = 1,2,3,...
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}