The sequence given is an arithmetic sequence with a common difference of 10 between each term. To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference. In this case, the first term a_1 is 15, the common difference d is 10, so the nth term a_n = 15 + (n-1) * 10 = 15 + 10n - 10 = 10n + 5.
The nth term is: 5n
The nth term is: 5-6n
n2
Give me a answer
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
The nth term is: 5n
The nth term is: 5-6n
The nth term is 25-4n and so the next term will be 5
n2
It is 4n+5 and so the next term will be 25
Give me a answer
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2
It is: 27-2n
t(n) = 28-3n where n = 1,2,3,...
Well, darling, the sequence you've got there is just the perfect squares of numbers. The 8th term would be the square of the 8th number, which is 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64. Keep those brain cells sharp, honey!
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.