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Any number that you choose can be the nth number. It is easy to find a rule based on a polynomial of order 4 such that the first four numbers are as listed in the question followed by the chosen number in the nth position. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example, U(n) = (3*n^4 - 30*n^3 + 105*n^2 - 126*n - 120)/4 gives the next number as 0orU(n) = (19*n^4 - 190*n^3 + 665*n^2 - 806*n - 696)/24 gives the next number as 1and so on.
The simplest solution, though, based on a polynomial of order 3 is U(n) = 6*(x - 8)
To find the nth term of a sequence, we first need to identify the pattern or rule by which the sequence is increasing or decreasing. In this case, the sequence is decreasing by 6 each time. So, the common difference between each term is -6. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference. Plugging in the values, we get a_n = -42 + (n-1)(-6) = -42 - 6n + 6 = -6n - 36. Therefore, the nth term of the sequence is -6n - 36.
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What is nth term of this sequence 16 22 30 40?
6n+10
What is the 30th term of the sequence when the nth term is 3n-1?
When n=30, 3n-1 = 89 .
What is nth term for sequence 30 27 24 21?
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
What is the nth term rule of the quadratic sequence below 4 , 15 , 30 , 49 , 72 , 99 , 130 , . . .?
fsedaz sd
Find nth term for sequence 0 5 10 15 20 25 30 35?
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
If the nth term of a sequence is 12n-6 what is the 8th term?
90
What number comes next in the sequence 30 24?
There are not enough numbers to be certain. The rule for the nth term could be Subtract 6 from the previous term giving 30, 24, 18, etc or Multiply previous term by 0.8 giving 30, 24, 21.6, etc etc
What is nth term of this sequence 16 22 30 40?
6n+10
Why is the nth term n2 5 if the sequence is 6 9 14 21 30?
Clearly here the nth term isn't n25.
What is the 30th term of the sequence when the nth term is 3n-1?
When n=30, 3n-1 = 89 .
What is the nth term for 3 10 17 24 31?
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4
What is nth term for sequence 30 27 24 21?
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
What is the 30th term of the sequence -5 -2 1 4 and 7?
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
What is the formula for the nth term of this sequence 14 22 30 38 46?
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
What is the nth term rule of the quadratic sequence below 4 , 15 , 30 , 49 , 72 , 99 , 130 , . . .?
fsedaz sd
Find nth term for sequence 0 5 10 15 20 25 30 35?
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
What are the first 5 terms in the sequence whose nth term is given by 30-2n?
Well, darling, the first 5 terms in that fancy sequence are 28, 26, 24, 22, and 20. You get those numbers by plugging in n values 1 through 5 into the formula 30-2n. So, there you have it, sweet cheeks!
