To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by consecutive odd numbers: 10, 14, 18, 22, and so on. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this sequence, a_1 = 6 and the common difference is 10. Therefore, the nth term can be expressed as a_n = 6 + (n-1)10.
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Oh, what a delightful sequence you have there! To find the nth term, we first need to identify the pattern. It looks like the differences between consecutive terms are increasing by 4 each time. So, the nth term can be calculated using the formula: nth term = 2n^2 + 2. Happy calculating, my friend!
Oh, dude, you just gotta subtract the previous term and see the pattern. The differences are 10, 14, 18, 22... it's like adding 4 more each time. So, the nth term would be 6 + 4(n-1) = 4n + 2. Easy peasy lemon squeezy!
I made a program that made the next 25is sequences after 16. It starts at #3 because 30 is #3 Here it is:
30
48
70
96
126
160
198
240
286
336
390
448
510
576
646
720
798
880
966
1056
1150
1248
1350
1456
1566
1680
Well, darling, the nth term of the sequence 6, 16, 30, 48, 70 is n^2 + 5. So, if you plug in n=1, you get 6, n=2 gives you 16, n=3 spits out 30, and so on. It's as simple as that, sugar.
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
Sn = 3n2 + 2n - 8
We note the sequence goes up in steps of '8' Hence '8n'. Next for step #1 4#1 ; n = 1 ; 8(1) + c = 16 8 + c = 16 c = 8 Hence the nth terms is 8n + 8 Verifications When n = 3 ; 8(3) + 8 = 24 + 8 = 32 ( which is true).