We note that the numbers rise by addition of ;7;7 between terms.
Hence we can write 7n .
The first term( n- 1) is '9'
So we can write
7(1) + c = 9
7 + c = 9
c = 2
So the nth term becomes 7n + 2
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The sequence is 2 larger than the 7 times table.
The nth term can be expressed as 7n + 2.
6n+10
30
t(n) = 5 - 7n for n = 1, 2, 3, ... The difference between each term is -7, therefore the nth term will be: t(n) = -2 + -7 × (n - 1) = -2 + 7n + 7 = 5 - 7n
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by consecutive odd numbers: 10, 14, 18, 22, and so on. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this sequence, a_1 = 6 and the common difference is 10. Therefore, the nth term can be expressed as a_n = 6 + (n-1)10.