t(n) = 5 - 7n for n = 1, 2, 3, ...
The difference between each term is -7, therefore the nth term will be:
t(n) = -2 + -7 × (n - 1) = -2 + 7n + 7 = 5 - 7n
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 27-2n
5, 11, 17, 23, 29
the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
It is: 27-2n
tn = n2 - n + 3It is 75359152333455975
5, 11, 17, 23, 29
the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)
The nth term is 7n-5 and so the 6th term will be 37
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is 3(n+1). The twenty-third term is equal to 3 x (23 + 1) = 72
It is T(n) = n2 + 4*n + 2.