.5M
pH = -log(hydronium concentration) [Hydronium is H3O.-log(1 x 10-9) = 9
Definition to use for the log (logarithm):the logarithm of a number (n) to a given base (b) is the exponent (e) to which the base must be raised in order to produce that number.(Raising to the power is the inverse of taking the logarithm.)logb(n) = e or be = nFor example, the logarithm of 1000 to base 10 is 3 ( log10(1000) = 3),because 10 to the power of 3 is 1000: 103 = 1000.-log10[H+] is (by definition) used to calculate the pH of a dilute solution in which [H+] = concentration of H+ (or H3O+) in mol/L.pH = -log10[H+] or [H+] = 10-pH
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
The concentration of H3O+ (hydronium ions) in a solution can be calculated using the formula pH = -log[H3O+], where [H3O+] represents the molarity of the hydronium ions. This formula relates the acidity of a solution to the concentration of hydronium ions present.
If the concentration of H3O+ and OH- ions are equal, the solution is neutral with a pH of 7. This is because in neutral water, the concentration of H3O+ ions (from dissociation of water) is equal to the concentration of OH- ions.
The concentration of an acid or base is measured in terms of the pH scale, which indicates the presence of H3O+ ions in solution. A lower pH value indicates a higher concentration of H3O+ ions, representing a more acidic solution. A higher pH value indicates a lower concentration of H3O+ ions, representing a more basic solution.
The pure water has the pH=7; the concentrations of OH- and H3O + are equivalent.
In a given solution, the H3O concentration is directly related to the D3O concentration. This means that as the H3O concentration increases, the D3O concentration also increases, and vice versa.
The concentration of H3O+ ions can be calculated using the formula pH = -log[H3O+]. Rearrange the formula to get [H3O+] = 10^(-pH). Plugging in the pH value of 2.32 gives a concentration of H3O+ ions of approximately 4.63 x 10^(-3) M.
If the concentration of H3O+ ions is greater than the concentration of OH- ions in a solution, the solution is considered acidic. This imbalance indicates that there are more protons than hydroxide ions present, leading to an acidic pH.
The H3O+ concentration in a solution with pH 3.22 = 1x10^-3.22 M or 6.03x10^-4 M.If a solution is 100 times less acidic, then the H3O+ concentration will be 6.03x10^-6 M.Put another way, 100 times less acidic will have a pH of 5.22 and H3O+ = 1x10^-5.22 = 6.03x10^-6M
The pH of a solution is a measure of the concentration of hydronium ions (H3O+) present. A lower pH value indicates a higher concentration of H3O+ ions, making the solution more acidic. Conversely, a higher pH value indicates a lower concentration of H3O+ ions, making the solution more basic.
The concentration of OH- for a solution with H3O+ concentration of 1x10^-5 M can be found by using the ion product constant of water (Kw = 1.0x10^-14) to calculate the OH- concentration. Since H3O+ and OH- are related by Kw = [H3O+][OH-], you can solve for [OH-] by rearranging the equation. This will give you a value of 1.0x10^-9 M for the OH- concentration.
To determine the concentrations of H3O and OH- ions from the pH of a solution, you can use the formula: pH -logH3O. From this, you can calculate the concentration of H3O ions. Since the product of H3O and OH- ions is constant in water (1.0 x 10-14 at 25C), you can then find the concentration of OH- ions by dividing this constant by the concentration of H3O ions.
H3O+ concentration in a 0.048 M NaOH solution is 2.4 x 10^-12 M. This is because NaOH is a strong base that dissociates completely in water to produce Na+ and OH- ions, which react with any H3O+ ions to form water. As a result, the H3O+ concentration in such a solution is extremely low.