C.
12,000; 2,800; 24
Do you mean, what is the hundreds column of 3706: 3706 has a 7 in the hundreds column, so there are 7 hundreds. Or do you mean what is 3706 divided by 100: 3706 ÷ 100 = 37.06
how to find the partial products of a number
The partial products for 734X29 are 6,606 and 14,680.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
the partial products is 2,480 and 310
Partial products for 4 and 0.91 involve breaking down the multiplication process. You can express 0.91 as 0.90 + 0.01. Then, multiply each part by 4: (4 \times 0.90 = 3.60) and (4 \times 0.01 = 0.04). Finally, add the partial products together: (3.60 + 0.04 = 3.64).
To multiply 4 by 68 using partial products, you can break down 68 into its place values: 60 and 8. Then, you would calculate the partial products: 4 times 60 equals 240, and 4 times 8 equals 32. Finally, you would add the two partial products together: 240 + 32 equals 272.
The Bold and the Beautiful - 1987 1-3706 was released on: USA: 4 January 2002
80 + 24
32 and 160
Do you mean, what is the hundreds column of 3706: 3706 has a 7 in the hundreds column, so there are 7 hundreds. Or do you mean what is 3706 divided by 100: 3706 ÷ 100 = 37.06
how to find the partial products of a number
To find the partial product of 4 x 27, you can break down 27 into its components. For example, 27 can be expressed as 20 + 7. Then, you calculate the partial products: 4 x 20 = 80 and 4 x 7 = 28. Adding these together gives you a total of 80 + 28 = 108, so the partial products lead to the final result of 4 x 27 = 108.
The partial products for 734X29 are 6,606 and 14,680.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
the partial products for 12 and 3 30 and 6 :)
5630 is a single number and single numbers do not have partial products.