12 ****************************** 11, 16, 22 are the 3 numbers continuing the pattern.
consecutive square numbers
the highest sum of the numbers is 17 and the lowest is 1. The only perfect squares in that range are 1,4,9, and 16. That means the following numbers will work: 10,13.18,22,27,31,36,40,45,54,63,72,79,81,88, and 90; that is 16 numbers
The next numbers in the series are 32 and 57. This is reached by adding successive square numbers 1, 4, 9, 16, 25 and so on.
The numbers are 1 and 16 because 1+16 = 17 and 1 times 16 = 16
The pattern of these numbers is the square numbers. Therefore, following 42 = 16 comes 52 = 25, 62 = 36, 72 = 49.
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
12 ****************************** 11, 16, 22 are the 3 numbers continuing the pattern.
Other possible answers: 1+1+16+25 1+1+9+16+16 ... the pattern you see though is that there is no combination of square numbers greater than 1 that adds up to 43.
consecutive square numbers
no it is not a recursive pattern because it isn't equal numbers.
the highest sum of the numbers is 17 and the lowest is 1. The only perfect squares in that range are 1,4,9, and 16. That means the following numbers will work: 10,13.18,22,27,31,36,40,45,54,63,72,79,81,88, and 90; that is 16 numbers
These are the square numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81...
I think it is 100,000,000...I used the procedure below 1 = 1, which is 12 1+3 = 4, which is 22 1+3+5 = 9, which is 32 1+3+5+7=16, which is 42 ...and so on, so the sum of the first 10,000 odd numbers following this pattern would be 10,0002 or 100,000,000
11 and 31 and all the fives between numbers.
The next numbers in the series are 32 and 57. This is reached by adding successive square numbers 1, 4, 9, 16, 25 and so on.
this is just squaring the numbers 1 to 12, resulting in the following numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144