K=39.100
Cl=35.457
O3=48.000
total=122.557
%K = 39.1x100/122.557
%Cl = 35.457x100/122.557
%O = 48.0x100/122.557
error in calculation or your final product is impure and has residuals of chemicals that were supposed to dissappear
Get it CMH Calculation
To find 12 percent of 800g, you can multiply 800 by 0.12. This calculation gives you 96g, which is 12 percent of 800g. The formula for calculating a percentage is (percentage/100) x total amount, where in this case, the percentage is 12, and the total amount is 800g.
To convert a percentage to a decimal, you divide the percentage by 100. Therefore, to convert 473 percent to a decimal, you divide 473 by 100. This calculation gives you 4.73 as the decimal equivalent of 473 percent.
Parentheses
KCIO3 is nothing. KClO3 (with a lowercase L) is potassium chlorate.
This is simply because percentage means per 100.
A percentage is a portion of 100. so to find the calculation of a decreased percentage, you subtract.
CuSO4 - Copper Sulphate KCIO3 - NH4OH - Ammonium Hydroxide K2CO3 - Potassium Carbonate NA2SO4 - Sodium Sulphate KC2H3O2 -
It is a calculation that determines the % of cost to sales.
HCN is an acid; KClO3 is a salt.
CGPA 9/10
Russia's literacy rate to my calculation's is 99.4% out of 100
69. 00 g of oxygen
the gradability of a vehicle calculation is depend on rise and run of the vehcile. it is calculated in percentage. percentage of gradability = (rise/run)*100
To balance the chemical equation KCIO3 → KCI + O2, you need to make sure the number of atoms on both sides is equal. First, balance the potassium atoms by adding a coefficient of 1 in front of KCI. Next, balance the chlorine atoms by adding a coefficient of 1 in front of KCI. Finally, balance the oxygen atoms by adding a coefficient of 3 in front of O2. The balanced equation is KCIO3 → KCI + 3O2.
There is no such thing as KCIO3. That should be a lowercase L, not an I. (all two-letter element symbols use a lowercase for the second letter) That being said, KClO3 is Potassium Chlorate. K = Potassium Cl = Chlorine O = Oxygen 3 = number of Oxygen atoms in the molecule