24CM
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
Well, honey, making a shape with a perimeter of 9cm is as easy as pie. You could have a triangle with sides measuring 3cm, 3cm, and 3cm. Or you could have a rectangle with sides measuring 2cm and 2.5cm. Just remember, the perimeter is the sum of all the sides, so get those measuring tapes out and get creative!
With 3cm for each sides.
3cm + 4cm + 3cm + 4cm = 14 cm
To find the perimeter of something all you have to do is, MEASURE THE DISTANCE AROUND THE OBJECT, for example if you have a triangle and the left side is 8cm, the right side is 5cm, and the bottom is 3cm, add the three measurements, 8cm + 5cm + 3cm = 16cm
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
The perimeter of a closed shape is its the lengths of all of it's sides added together. 8+6+2+5+3+8=32 cm. xx effy
i need help
24CM
Two sides of 8cm & two sides of 3cm fit the problem. 8+8+3+3=22cm (the perimeter you stated) AND a rectangle of 8x3cm is an area of 24cm2
6
It is: 7+8+12 = 27 cm
The area is 12cm2
A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
lwh=V 8*8*3=192 square centimeters.
Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm