just add them all together. 8+8+3+3 =22 CM
24CM
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
With 3cm for each sides.
3cm + 4cm + 3cm + 4cm = 14 cm
P = 46 cm A = 120 sq cm
To find the perimeter of something all you have to do is, MEASURE THE DISTANCE AROUND THE OBJECT, for example if you have a triangle and the left side is 8cm, the right side is 5cm, and the bottom is 3cm, add the three measurements, 8cm + 5cm + 3cm = 16cm
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
The perimeter of a closed shape is its the lengths of all of it's sides added together. 8+6+2+5+3+8=32 cm. xx effy
i need help
24CM
6
Two sides of 8cm & two sides of 3cm fit the problem. 8+8+3+3=22cm (the perimeter you stated) AND a rectangle of 8x3cm is an area of 24cm2
It is: 7+8+12 = 27 cm
The area is 12cm2
A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
lwh=V 8*8*3=192 square centimeters.
Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm