This is an Arithmetic Progression or Sequence with an Initial Term (a) of 10 and a Common Difference (d) of -3
The standard formula is U(n) = a + (n - 1)d
Substituting the values for a and d gives :-
U(n) = 10 + [(n - 1) x (-3)] = 10 - 3n + 3
We can write this as, 13 - 3n but it is common practice to retain the initial term (10)............so, U(n) = 10 - 3(n - 1)
Then U(5) = 10 - 3(5 - 1) = 10 - 12 = -2 which confirms the value shown in the question.
If the term number is n, then the nth term is 10(n-1) +8.
The nth term is 4n - 3
10n + 1
It could be 3691. Use the position to term rule: t(n) = (856n3 - 5091n2 + 9545n - 5304)/6 for n = 1, 2, 3, ...
PRIME
If the term number is n, then the nth term is 10(n-1) +8.
The nth term is 4n - 3
1 2 3 4 5 2 5 8 11 14 ... If this is the sequence, the position-to-term rule is 3n-1. However, it could be another sequence depending on the rest of the terms.
term n = 3n - 1 for n = 1, 2, 3, ...
The position to term rule in mathematics refers to a method used to identify the terms of a sequence based on their position or index. For example, in an arithmetic sequence, the nth term can be expressed as a linear function of n, typically in the form (a_n = a + (n-1)d), where (a) is the first term and (d) is the common difference. This rule helps in finding specific terms without listing the entire sequence. It's also applicable in other types of sequences, such as geometric sequences, where the nth term is determined by a different formula.
t(n) = 50 - 2n where n = 1, 2, 3, ...
To find the first, fourth, and tenth terms of the arithmetic sequence defined by the rule ( A(n) = 1 + (n - 1)(-4.1) ), we can substitute ( n ) with 1, 4, and 10. For ( n = 1 ): ( A(1) = 1 + (1 - 1)(-4.1) = 1 ). For ( n = 4 ): ( A(4) = 1 + (4 - 1)(-4.1) = 1 - 12.3 = -11.3 ). For ( n = 10 ): ( A(10) = 1 + (10 - 1)(-4.1) = 1 - 36.9 = -35.9 ). Thus, the first term is 1, the fourth term is -11.3, and the tenth term is -35.9.
1, 4, 7, 10, 13, …
Term to Term rule in Maths is how much you go up or down in. e.g 1,2,3,4,5,6 would be +1
10n + 1
The pattern consists of the cubes of consecutive integers. Specifically, the numbers are (1^3), (2^3), (3^3), (4^3), and (5^3), resulting in 1, 8, 27, 64, and 125, respectively. The rule for this pattern is that each term is equal to (n^3), where (n) is the position of the term in the sequence (starting from 1).
The rule is multiply the previous term by -1 to find the next term.