This is an Arithmetic Progression or Sequence with an Initial Term (a) of 10 and a Common Difference (d) of -3
The standard formula is U(n) = a + (n - 1)d
Substituting the values for a and d gives :-
U(n) = 10 + [(n - 1) x (-3)] = 10 - 3n + 3
We can write this as, 13 - 3n but it is common practice to retain the initial term (10)............so, U(n) = 10 - 3(n - 1)
Then U(5) = 10 - 3(5 - 1) = 10 - 12 = -2 which confirms the value shown in the question.
If the term number is n, then the nth term is 10(n-1) +8.
The nth term is 4n - 3
It could be 3691. Use the position to term rule: t(n) = (856n3 - 5091n2 + 9545n - 5304)/6 for n = 1, 2, 3, ...
PRIME
5321.0978 (is the example) 5 is in the thousands position (1,000) 3 is in the hundreds position (100) 2 is in the tens position (10) 1 is in the ones position (1) 0 is in the TENTH'S (1/10) position 9 is in the HUNDREDTH'S (1/100) position 7 is in the THOUSANDTH's (/1000) position 8 is in the TEN-THOUSANDTH'S (10000) position
If the term number is n, then the nth term is 10(n-1) +8.
The nth term is 4n - 3
1 2 3 4 5 2 5 8 11 14 ... If this is the sequence, the position-to-term rule is 3n-1. However, it could be another sequence depending on the rest of the terms.
term n = 3n - 1 for n = 1, 2, 3, ...
t(n) = 50 - 2n where n = 1, 2, 3, ...
Term to Term rule in Maths is how much you go up or down in. e.g 1,2,3,4,5,6 would be +1
1, 4, 7, 10, 13, …
The rule is multiply the previous term by -1 to find the next term.
It could be 3691. Use the position to term rule: t(n) = (856n3 - 5091n2 + 9545n - 5304)/6 for n = 1, 2, 3, ...
addend
hi Wat is order 1 rule 10
38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...