10n + 1
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The given sequence is an arithmetic sequence with a common difference of 10 between each term. The formula for finding the nth term of an arithmetic sequence is: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the position of the term, and (d) is the common difference. In this case, the first term (a_1) is 11 and the common difference (d) is 10. Therefore, the nth term for this sequence is (11 + (n-1) \times 10).
2n^2-1
+9
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
The nth term is 7n-4 and so the next number in the sequence is 31
To find the seventh term in the sequence -6, -11, -16, -21, -26, we first identify the pattern: each term decreases by 5. Therefore, the next term would be -26 - 5 = -31. Continuing this pattern, the seventh term would be -31 - 5 = -36.