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In single die,

S = {1,2,3,4,5,6} So n(S) = 6

The event A is defined as getting a number less than 3.

A = {1,2} So n(A)=2

Hence P(A) = n(A)/n(S) = 2/6 =1/3

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14y ago
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Q: What is the probability of getting a number less than 3 in two tosses of a single die?
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