In single die,
S = {1,2,3,4,5,6} So n(S) = 6
The event A is defined as getting a number less than 3.
A = {1,2} So n(A)=2
Hence P(A) = n(A)/n(S) = 2/6 =1/3
The probability is 0.0322
33%
The experimental probability of a coin landing on heads is 7/ 12. if the coin landed on tails 30 timefind the number of tosses?
75%. There are 3 possible ways of getting at least one tail from 2 tosses from a coin:Tail & Tail orHead & Tail orTail & HeadEach of these individual outcomes has a probability of 25% (e.g. the probability of getting a tail and then another tail is 25%). Adding the possible outcomes together gives you a total of 75%.
1/2 or 5/10
2 out of 6
In a large enough number of tosses, it is a certainty (probability = 1). In only the first three tosses, it is (0.5)3 = 0.125
The probability of two tails on two tosses of a coin is 0.52, or 0.25.
The probability is 0.0322
The probability is 1/4
The probability is 1 out of 5
0.5
If the coin is fair, the probability of getting all heads will decrease exponentially towards 0.
1/4
The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.
It is 3/8.
2 out of 3 i think