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Assuming that by a difference of 1 you mean rolling a pair (2) of dice and then subtracting the two numbers that you get individually on each die. Well there are 36 total possibilities. To get a difference of 1 you need a 6&5, 5&4, 4&3, 3&2, or 2&1.

That represents 10 chances. not getting this is 36-10 = 26 chances.

So the probability = 28 / 36 = 7/9.

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11y ago

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Q: What is the probability of not rolling the difference of1?
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