Assuming that by a difference of 1 you mean rolling a pair (2) of dice and then subtracting the two numbers that you get individually on each die. Well there are 36 total possibilities. To get a difference of 1 you need a 6&5, 5&4, 4&3, 3&2, or 2&1.
That represents 10 chances. not getting this is 36-10 = 26 chances.
So the probability = 28 / 36 = 7/9.
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The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
assuming a single six sided die the probability of rolling a three is 1/6
The probability of rolling a 4 in a die is 1 in 6, or about 0.1667. The probability, then, of rolling a 4 in at least one of two dice rolls is twice that, or 2 in 6, or 0.3333. The probability of rolling a sum of 4 in two dice is 3 in 36, or 1 in 18, or about 0.05556.
The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice