I am not sure but I think 3/36
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
7
The probability that any number will come up on one cube is 1/6. 1/6*1/6=1/36 the probability is 1/36
possible ways to get 7: 1+6=7 6+1=7 2+5=7 5+2=7 3+4=7 4+3=7 6 possible ways to get 7. There are 36 possible ways the two dice could be rolled, so you would get 6/36 or in this case, 35/210 Answer:35
4/12
The probability is 1/36.
The probability is 21/36 = 7/12
I am not sure but I think 3/36
On a roll of two dice, the chance of rolling a 3 (one and two) is 2 in 36, or 1 in 18 when reduced.
Pr(7) = 1/36 Pr(11) = 2/36 = 1/18
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
Assuming that these number cubes are ordinary dice (number are 1-6) and that both dice are balanced (equal chances for each side to turn up), then it's 1/36. There are 36 different possibilites for the upturned faces when a pair of dice is rolled, one of which is "4 and 4".
Three out of twelve
There are 12 squares on 2 cubes
The probability is 0.277... (repeating).
7