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Q: Two number cubes are rolled what is probubility of 1 and 2?

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I am not sure but I think 3/36

The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36

7

The probability that any number will come up on one cube is 1/6. 1/6*1/6=1/36 the probability is 1/36

possible ways to get 7: 1+6=7 6+1=7 2+5=7 5+2=7 3+4=7 4+3=7 6 possible ways to get 7. There are 36 possible ways the two dice could be rolled, so you would get 6/36 or in this case, 35/210 Answer:35

Related questions

With two fair cubes, the probability is 1/6.

4/12

The probability is 1/36.

The probability is 21/36 = 7/12

I am not sure but I think 3/36

On a roll of two dice, the chance of rolling a 3 (one and two) is 2 in 36, or 1 in 18 when reduced.

Pr(7) = 1/36 Pr(11) = 2/36 = 1/18

The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36

There are 12 squares on 2 cubes

7

Assuming that these number cubes are ordinary dice (number are 1-6) and that both dice are balanced (equal chances for each side to turn up), then it's 1/36. There are 36 different possibilites for the upturned faces when a pair of dice is rolled, one of which is "4 and 4".

It is 1/12.

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