I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.
i think it is 1 because if you divide 1 in to 8 you will get 1.8 and the 2 so that is the answer so yall do not know the answe r because yall dumb
Well, if the spinner has equal sections, and green is one of them, then statistically speaking, you would expect it to land on green about 100 times out of 600 spins. But hey, life's full of surprises, so don't bet your retirement savings on it!
A probability can be any number between 0 and 1. Zero simply means there is not a possibility of something occurring. One means it is absolutely certain to occur.
8 + 3 = 11The number is three
Expressed as a decimal fraction, this is equal to 8.4.
The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
17 out of 21
The probability is 3/7.
The probability is 5/9.
6-52
To find the probability of the pointer landing on 3, you need to know the total number of equal sections on the spinner. If the spinner has ( n ) sections, and one of them is labeled 3, the probability is calculated as ( \frac{1}{n} ). For example, if there are 8 sections, the probability would be ( \frac{1}{8} ). Without knowing the total number of sections, the exact probability cannot be determined.
6-52
i think it is 1 because if you divide 1 in to 8 you will get 1.8 and the 2 so that is the answer so yall do not know the answe r because yall dumb
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.
It depends on how many sides the spinner has, a detail that was not provided in the question. If the spinner has 7 sides, and there is only one 3, then the probability of landing on a 3 is 1 in 7, or about 0.1429.
There are ten possible events: that the spinner shows one of the number from 1 to 10. The probability of each of these events is the same and equals 1/10, 0.1 or 10%