The probability is
(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
The probability is 5/9.
The probability is 3/7.
6-52
It depends on how many sides the spinner has, a detail that was not provided in the question. If the spinner has 7 sides, and there is only one 3, then the probability of landing on a 3 is 1 in 7, or about 0.1429.
The chance of receiving a blue result is 2 in 4, in other words 50%.
17 out of 21
The probability is 3/7.
The probability is 5/9.
6-52
I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.
6-52
It depends on how many sides the spinner has, a detail that was not provided in the question. If the spinner has 7 sides, and there is only one 3, then the probability of landing on a 3 is 1 in 7, or about 0.1429.
There are ten possible events: that the spinner shows one of the number from 1 to 10. The probability of each of these events is the same and equals 1/10, 0.1 or 10%
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
i think it is 1 because if you divide 1 in to 8 you will get 1.8 and the 2 so that is the answer so yall do not know the answe r because yall dumb
The chance of receiving a blue result is 2 in 4, in other words 50%.