The probability is
(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
The probability is 3/7.
The probability is 5/9.
6-52
It depends on how many sides the spinner has, a detail that was not provided in the question. If the spinner has 7 sides, and there is only one 3, then the probability of landing on a 3 is 1 in 7, or about 0.1429.
The chance of receiving a blue result is 2 in 4, in other words 50%.
17 out of 21
The probability is 3/7.
The probability is 5/9.
6-52
I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.
To find the probability of the pointer landing on 3, you need to know the total number of equal sections on the spinner. If the spinner has ( n ) sections, and one of them is labeled 3, the probability is calculated as ( \frac{1}{n} ). For example, if there are 8 sections, the probability would be ( \frac{1}{8} ). Without knowing the total number of sections, the exact probability cannot be determined.
To determine how many times you would expect to land on 3 after spinning the spinner 20 times, you need to know the probability of landing on 3 in a single spin. If the spinner has an equal number of sections, you can find the probability by dividing the number of sections that include 3 by the total number of sections. Multiply that probability by 20 to get the expected number of times landing on 3. For example, if the spinner has 4 equal sections, the expected number would be (20 \times \frac{1}{4} = 5).
6-52
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.
There are ten possible events: that the spinner shows one of the number from 1 to 10. The probability of each of these events is the same and equals 1/10, 0.1 or 10%
It depends on how many sides the spinner has, a detail that was not provided in the question. If the spinner has 7 sides, and there is only one 3, then the probability of landing on a 3 is 1 in 7, or about 0.1429.