The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80.
Algebraically, the equation to find the four integers is :
[x + (x+2) + (x+4) + (x+ 6)]/4 = 7
(4x + 12) / 4 = 7
x + 3 = 7
x = 4
x+2 = 6 // x+4 = 8 // x+6 = 10
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
There is no set of two consecutive integers equating to 200.
The two consecutive odd integers having a product of 99 are 9 and 11.
what is the formula to use to solve the product of two consecutive odd integers
I think you mean consecutive even integers: 20 & 22
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
-13, -15 and -17
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
9240 is the product of the three consecutive integers 20, 21, and 22.
Consecutive odd integers would be 5 and 7.
There is no set of two consecutive integers having a product of 14. Product means the result of multiplication.
There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.
There are no two consecutive integers, negative or positive, whose product is 440.
No, it is not. It is the sum of two consecutive integers: 46 and 47.
There is no set of two consecutive integers equating to 200.
The two consecutive odd integers having a product of 99 are 9 and 11.
what is the formula to use to solve the product of two consecutive odd integers