1
10-m
5m + 13
2 m south
m = 15
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
5 decreased by 4 times m=1 Step-by-step: 1)5-4m 2)1m (When a letter is alone, it means it is 1) 3)1x1 (When a number is next to a number, it means multiply) Answer is 1
5(m-2) - m(m-2)
(m + 2) - x
5(m-2) - m(m-2)
5(m-2) - m(m-2)
You need to find factors whose sum is 10 and product is 25. Here, it is a square, and the number is 5. m^2 +10m +25 = (m+5)(m+5)
m+5/2=m/2+5/2
(5-2x+m)2
1
10-m
Let the number be 'm' & 'n' Hence Product ; mn = 80 Sum ; m + n = 21 m = 21 - n Substitute (21 - n) n = 80 21n - n^2 = 80 n^2 - 21 n + 80 = 0 It is now in quadratic form to factor. ( n - 16)(n - 5) = 0 Hence the numbers are 5 & 16