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5(m-2) - m(m-2)

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Lelia Bins

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2y ago
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Q: What is m 2?
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Related questions

What is m-2 over m plus 2 times m over m-1?

(m-2)/(m+2) * m/(m-1) = [(m-2)*m]/[(m+2)*(m-1)] = (m2 - 2m)/m2 + m - 2)


What is 5(m-2) - m(m-2)?

5(m-2) - m(m-2)


What is is 2 m?

5(m-2) - m(m-2)


What is the answer to m plus m when equals 2?

m+m when m equals 2. 2+2 4


What is 'm2-m-3 times m-4?

( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7


What are the factors of the quadratic function -m2 3m-2?

-m2+3m-2 -m2+2m+m-2 -m(m -2)+1(m-2) (-m+1)(m-2) or


If m plus 9 equals 2 what is m?

m + 9 = 2 Therefore, m = 2 - 9 m = -7


7m(m-2) plus 6n(2-m)?

factor by grouping 7m(m-2)+6n(2-m)


The sum of the squares of two consecutive positive numbers is 85?

Let the numbers be m & m+1 (consecutive) Hence their squares are m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2 Hence Their sum is m^2 + m^2 + 2m + 1 = 85 2m^2 + 2m - 84 = 0 m^2 + m - 42 =0 Factor (m + 7)(m - 6) = 0 Hence the numbers are 6 & 7 .


Find two consecutive positive even numbers the sum of whose squares is 340?

Let the number be 'm' & 'm + 2' Hence their squares are m^2 & (m+2)^2 There sum is m^2 + (m+2)^2 = 340 Multiply out he brackets m^2 + m^2 + 4m + 4 = 340 . 2m^2 + 4m + 4 = 340 Divide both sides by '2' m^2 + 2m + 2 = 170 m^2 + 2m - 168 = 0 Factor (m - 12)(m + 14) = 0 Hence m = 12 & m+ 2 = 14 The two consecutive even numbers. 12^2 = 144 14^2 = 196 144 + 196 = 340 As required.


What is the answer to m2-8m equals -16?

if by m2 you mean m multiplied by 2, then m= 2 2/3if by m2 you mean m squared, then m still =2 2/3, because the m squared becomes m times m which equals 2m


M minus 4 greater than -2?

6