6 x 8 x 4 = 48 x 4 = 96 x 2 = 192
The number are 2 and 4
8 X (3/4) = 24/4 = 6
4*4 = 16 (4+4 = 8)3*5 = 15 (3+5 = 8)2*6 = 12 (2+6 = 8)1*7 = 7 (1+7 = 8)0*8 = 0 (0+8 = 8)So 4 and 4 produce the largest product and still have the sum of 8.Assumptions:only integers,that this can be extrapolated (-1*9 < 0*8 etc)
Your a bum 4 lising 2 me 2 4 6 8 2 4 8 6 2 6 4 8 2 6 8 4 2 8 4 6 2 8 6 4 4 2 6 8 4 2 8 6 4 6 2 8 4 6 8 2 4 8 2 6 4 8 6 2 6 2 4 8 6 2 8 4 6 4 2 8 6 4 8 2 6 8 2 4 6 8 4 2 8 2 4 6 8 2 6 4 8 4 2 6 8 4 6 2 8 6 2 4 8 6 4 2 That's all 24 possible combinations.
(8*4) + (8-4) = 32 + 4 = 36 ^ ^ sum ^ product and difference
4 and 2: 2x4=8, 4+2...yea
40
-4 and -2
The product of 8 and 6 is 48.
The first three composite numbers are 4, 6, and 8. 8 x 6 x 4 = 192
The number are 2 and 4
12 and 4 or 6 and 8
-8
The product of 6, 10 and 8 is 480.
i have no clue Sum of 8 and 6=14 and product of "8 and sum of 8 and 6"=112
8 X (3/4) = 24/4 = 6
2