find the sum and product of the roots of 8×2+4×+5=0
5 x n = (3 x 16) - 8 5 x n = 48 - 8 5 x n = 40 n = 40/5 ie 8
It is 8*(-4)N which is -32N
n - 6m = 8 n = 6m + 8
-15
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
(9n - 8) should do it.
Is 4 cause it is equivalent to 2 n a multiple of 8 for example n./. 8 so that the answer
The product of 15 and a number (when the number is n) is 15n. Subtract 8 from this and we have 15n-8
find the sum and product of the roots of 8×2+4×+5=0
8n+6
5 x n = (3 x 16) - 8 5 x n = 48 - 8 5 x n = 40 n = 40/5 ie 8
8-x 8-x
It is 8*(-4)N which is -32N
8-n
A product of 3 and N would be 3 and N multiplied together, so the product would be 3N. To get a numeric answer, you would first need to find what the value of N is.
N = -12 + 8*(17+28) = -12 + 8*45 = -12+360 = 348