thousands
38.5
The product of the ten one-digit numbers is 0.
1, 2, 10, 11, 12, 20, 21, 22, 100, 101.
- There are an infinite number of "counting numbers" that are greater than 70. - There are also an infinite number of "counting number" that are multiples of 10. So.... since you used an "OR" statement, this mean how many number are true for both statements above. That would be: AN INFINITE NUMBER of counting numbers. In fact, if you had said "AND", it still would be an infinite number: 80, 90, 100, ... and so on FOREVER. * * * * * The above answer has interpreted the questions as "two-digit counting numbers greater than 70" OR "a multiple of ten". Apart from the fact that there are not an infinite number of two-digit counting numbers greater than 70, the answer would be correct. But the answer could be interpreted as "two digit counting numbers" that are "greater than 70" OR "a multiple of ten". In that case, the first set is {71, 72, ... 99} and the second is {10, 20, 30, ... 90} with an intersection set consisting of {80 and 90} So there are 29 + 9 - 2 = 36 such number.
thousands
38.5
2520
2520
2520
22
1, 2, 3, 4, 5, 6, 7, 8, 9 and 10!
1, 2, 3, 4, 5, 6, 7, 10, 11, 12
1, 2, 10, 11, 12, 20, 21, 22, 100, 101.
The product of the ten one-digit numbers is 0.
It is the lowest number that has the first ten counting numbers as factors.
-- Write down a list of the first ten whole numbers. -- For each one, multiply it by itself, and write the product next to it.