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So, in a parallelogram you have two sets of parallel lines. Take one set, and one of other lines and continue it beyond that set of two lines. Now, the single line is known as a tranversal, and by the same-side interior angles therom, the consecutive angles you are talking about must be congruent. The argument is the same on the opposite side. This is a lot easier with a diagram, ask your math teacher sometime.
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Does an irregular hexagons interior angles equal 720?
Yes. All hexagons have interior angles totalling 720 degrees, whether they are regular or irregular. The proof of this is fairly easy.
The sum of 3 consecutive odd numbers is 59 what are the numbers?
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.
Three consecutive numbers that add up to a multiple of three?
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
Prove that the bisectors of the angles of a linear pair are at right angle?
I am working on the same exact proof right now and i am lost
What is the proof that the sum of the angles of a hexagon equals 720?
There are 6 angles in a hexagon, and each angle measures 120 degrees. 120 x 6, or 120+120+120+120+120+120=720.
