In general 'to bisect' something means to cut it into two equal parts. The 'bisector' is the thing doing the cutting.
In an angle bisector, it is a line passing through the vertex of the angle that cuts it into two equal smaller angles.
Therefore it's in the definition.
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angle B and angle D are supplements, angle B is congruent to angle D, angle A is congruent to angle A, or angle A is congruent to angle C
triangle sum theorem
I am working on the same exact proof right now and i am lost
(1) triangle sum, (2) subtraction
The proof is fairly long but relatively straightforward. You may find it easier to follow if you have a diagram: unfortunately, the support for graphics on this browser are hopelessly inadequate.Suppose you have a rhombus ABCD so that AB = BC = CD = DA. Also AB DC and AD BC.Suppose the diagonals of the rhombus meet at P.Now AB DC and BD is an intercept. Then angle ABD = angle BDC.Also, in triangle ABD, AB = AD. therefore angle ABD = angle ADC.while in triangle BCD, BC = CD so that angle DBC = angle BDC.Similarly, it can be shown that angle BAC = angle CAD = angle DCA = angle ACB.Now consider triangles ABP and CBP. angle ABP (ABD) = angle CBP ( CBD or DBC),sides AB = BCand angle BAP (BAC) = angle BCP (BCA = ACB).Therefore, by SAS, the two triangles are congruent.In the same way, triangles BCP and CPD can be shown to congruent as can triangles CPD and DPA. That is, all four triangles are congruent.