Mass = 87 grams and density of aluminium = 2.7g/cm3
So volume of spere = Mass/Density = 87/2.7 = 32.22... cm3
Then V = 4/3*pi*r3 = 32.22.. cm3
r3 = 32.22...*3/(4*pi) = 7.6925 so that r = 1.97 cm
= 0.78 inches.
cuboid volume = 49 * 344 * 318 = 5,360,208 cu. cm.>(sphere) volume = 4/3 * pi *r3>radius = cube root ( (3* volume) / (4 * pi) ) = 108.566 cm
Since a sphere is round it is a shape without a face.
You can look at this problem by stating it differently. Basically we just need to find the volume of a sphere with a given diameter. If we look up the formula for the volume of a sphere we get: Volume equals four thirds times pi times the radius cubed. The radius of a sphere is equal to 1/2 of the diameter, and pi is equal to about 3.14. Using this information we can find the volume of our rubber ball. V=(4/3)*pi*(1/2d)^3 So if you had a rubber ball with a 2 in. diameter, you would have a volume of about 4.19 in^3. Hope that helps.
a sphere
For example, a sphere or an ellipsoid.
54.7
Density = mass / volume. You have the density of aluminum and the mass of the aluminum sphere. The volume of a sphere is 4/3*Pi*r^3. Therefore volume = 4/3*Pi*r^3 = mass / density. Solve for r, which is the radius of the sphere.
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
16
A steradian is the solid angle subtended at the centre of a sphere by radius r by a portion of the surface of the sphere which has area r2.
inner core
inner core
Sphere
It has a surface area of: 4*pi*radius squared It has a volume of: 4/3*pi*radius cubed
cuboid volume = 49 * 344 * 318 = 5,360,208 cu. cm.>(sphere) volume = 4/3 * pi *r3>radius = cube root ( (3* volume) / (4 * pi) ) = 108.566 cm
Since a sphere is round it is a shape without a face.
You need to know if the sphere is solid or hollow. You also need the "density" in terms of pounds weight per unit volume. Then Volume = Mass/Density And Radius = cuberoot[3*Vol/(4*pi)]