Mass = 87 grams and density of aluminium = 2.7g/cm3
So volume of spere = Mass/Density = 87/2.7 = 32.22... cm3
Then V = 4/3*pi*r3 = 32.22.. cm3
r3 = 32.22...*3/(4*pi) = 7.6925 so that r = 1.97 cm
= 0.78 inches.
cuboid volume = 49 * 344 * 318 = 5,360,208 cu. cm.>(sphere) volume = 4/3 * pi *r3>radius = cube root ( (3* volume) / (4 * pi) ) = 108.566 cm
Since a sphere is round it is a shape without a face.
You can look at this problem by stating it differently. Basically we just need to find the volume of a sphere with a given diameter. If we look up the formula for the volume of a sphere we get: Volume equals four thirds times pi times the radius cubed. The radius of a sphere is equal to 1/2 of the diameter, and pi is equal to about 3.14. Using this information we can find the volume of our rubber ball. V=(4/3)*pi*(1/2d)^3 So if you had a rubber ball with a 2 in. diameter, you would have a volume of about 4.19 in^3. Hope that helps.
a sphere
For example, a sphere or an ellipsoid.
Density = mass / volume. You have the density of aluminum and the mass of the aluminum sphere. The volume of a sphere is 4/3*Pi*r^3. Therefore volume = 4/3*Pi*r^3 = mass / density. Solve for r, which is the radius of the sphere.
The moment of inertia of a solid sphere is given by the formula (2/5) m r2, where m is the mass of the sphere and r is the radius of the sphere.
The formula for calculating the moment of inertia of a solid sphere is (2/5) m r2, where m is the mass of the sphere and r is the radius of the sphere.
16
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
The inner core of the Earth is a solid metallic sphere made primarily of iron and nickel with a radius of about 1216 kilometers. It is surrounded by the liquid outer core and the solid mantle.
A steradian is the solid angle subtended at the centre of a sphere by radius r by a portion of the surface of the sphere which has area r2.
inner core
To find the radius of the sphere, we need to know that the volume of the rectangular block is equal to the volume of the sphere. The volume of the rectangular block is 49 x 44 x 18 = 38,808 cm³. Equating this to the volume of a sphere (4/3πr³), we can solve for the radius which comes out to be approximately 22.18 cm.
Sphere
It has a surface area of: 4*pi*radius squared It has a volume of: 4/3*pi*radius cubed
cuboid volume = 49 * 344 * 318 = 5,360,208 cu. cm.>(sphere) volume = 4/3 * pi *r3>radius = cube root ( (3* volume) / (4 * pi) ) = 108.566 cm