4
The interval is, presumably, the range = 12.
10 8 4 5 8 6 12 1 Write these data in an increasing order: 1 4 5 6 8 8 10 12 The range of these data is the difference of the larger value and the smaller value: 12 - 1 = 11 Thus, the range is 11.
Mean: 3 I think the range is 7 or 8
8 and 12
333
To find the range of a set of numbers, subtract the lowest value from the highest; so the range is 12 - 4, or 8.
Range: 8 Median: 7.5 Mode: 8
First of all rearrange the terms (numbers) in rank order. Hence 3,4,6**,8**,8,9,9. The MEDIAN is the ABSOLUTE middle number in the rank, which is the first '8'. Note , there are three terms to either side of this '8'. The MODE is the number that appears most frequently (often) . Both '8' & '9' appear twice. So either '8' is the mode, or '9' is the mode. Neither number is incorrect. However, since '8' is also the median , it is probably the best to select '8'. The MEAN (Casually the Average) is the sum of all the terms divided by the number of terms. Hence [3+4+6+8+8+9+9] / 7 => [47]/7 = 6.714.... N.B. In Maths. it is the 'MEAN' . Casually in everyday life it is referred to as the average. However, the word 'average' comes from Latin ' Avaria' , for 'loss ' or 'damage.
The range of a value of numbers is equal to the largest minus the smallest. Therefore, in this instance, the range is equal to 9 - 4 = 5.
8 and 4
The interval is, presumably, the range = 12.
10 8 4 5 8 6 12 1 Write these data in an increasing order: 1 4 5 6 8 8 10 12 The range of these data is the difference of the larger value and the smaller value: 12 - 1 = 11 Thus, the range is 11.
4, 5, 5, 8, 8
Mean: 3 I think the range is 7 or 8
The smallest number is 1 and the largest number is 8. The range is the largest minus the smallest, so it is 8-1=7.
8 and 12
2 4 4 6 8