8 and 12 have a mean of 10 and a range of 4
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8 and 12 are the numbers.which has this mean is 10 and its range is 4
To find two numbers with a mean of 10 and a range of 8, we can set up a system of equations. Let x be the smaller number and y be the larger number. We know that (x+y)/2 = 10 (mean of 10) and y-x = 8 (range of 8). Solving these equations simultaneously, we get x = 6 and y = 14. Therefore, the two numbers are 6 and 14.
Range means the difference between the greatest and smallest numbers in a sequence of numbers. For example: 1,2,4,5,6,7,7,10,11 11-1=10, therefore the range is 10.
To find range you simply subtract the highest and lowest numbers in a set. So that means to find two numbers with a range of 7, you must choose two numbers that are 7 apart.Some numbers with a range of 7 are:-3 and 40 and 73 and 10
6 and 14 Solution x - y= 8, so x =8 + y, (x + y)/2 = 10, x + y = 20, Substituting x = 8 + y, we have: 2 y + 8 = 20, or 2y = 12, y = 6, x = 6+8= 14
As there are two numbers, the range is the difference between themAs there are 2 numbers the mean is exactly in the middle of them.Thus half the range is less than the mean and half the range is greater than the mean.Thus the two numbers are 10 ± (4/2) = 10 ± 2 = 8 and 12.Algebraically, this can be seen:Let the two numbers be x and y with y > xThen:their range is y - x = 4; andtheir mean is (x + y) / 2 = 10{2} can be rearrange to give x + y = 10 × 2 → y + x = 20adding {3} to {1} yields: (y + y) + (-x + x) = 20 + 4 → 2y = 24 → y = 12subtracting {1} from {3} yields (y - y) + (x - -x) = 20 - 4 → 2x = 16 → x = 8→ the two numbers are 8 and 12.