range iS given by -{2^(k-1) - 1 } to +{2^(k-1)-1} So putting k=7 range i from -63 to +63
Assuming the popular 2's complement is used, the range is from -24 to +24 - 1.
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
A signed 16 bit number can represent the decimal numbers -32768 to 32767.
Plus or minus 65,535
range iS given by -{2^(k-1) - 1 } to +{2^(k-1)-1} So putting k=7 range i from -63 to +63
A 5-bit binary counter, interpreted as an unsigned integer, has a range of 0 to 31. Interpreted as a two's complement signed integer, it has a range of -16 to +15.
Range of 8 bit signed number is -128 to 127 Reference: digital fundamentals by Floyd
Assuming the popular 2's complement is used, the range is from -24 to +24 - 1.
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
A signed 16 bit number can represent the decimal numbers -32768 to 32767.
A 32 binary number is a number stored by a computer in 32 bits. it can represent: 1) An unsigned number in the range 0 to 4,294,967,295 2) A signed number in the range -2,147,483,648 to 2,147,483,647 3) A single precision IEEE floating point number with 1 sign bit, 8 exponent bits and 23 mantissa bits give an accuracy of about 7.2 decimal digits and a range of ± 10^-38 to 10^38
+511
If a memory location is to contain a signed integer, then it will have a sign bit (zero means positive, one means negative). Also the negative numbers are represented by a complement (normally the two's complement). The article in the related link does a good explanation. What this means: for example, an 8 bit location could represent 256 possible numbers. In an unsigned situation, this would be 0 to 255. But in a signed situation, the range is -128 to +127.
Main Memory and Registers of just about every computer are based on 64-bit or 32-bit binary integers.
Plus or minus 65,535
No and Yes... No because as such the two numbers are different and convention will define what the bit pattern should represent. However, with 16 bits, the UNSIGNED bit pattern for 32768 is the same as the SIGNED pattern for -32768 BUT the two numbers are being represented in different ways (ie in different number systems). If the binary representation is a SIGNED number then the top bit will be set if it is negative and with 16 bits the possible range of numbers is -32768 to +32767 and so it is IMPOSSIBLE to represent +32768. With an UNSIGNED number of 16 bits the top bit has no such special meaning and the range possible is 0 to +65535, so it is IMPOSSIBLE to represent -32768. ie it is IMPOSSIBLE with 16 bits to represent -32768 and +32768 in the same number system as they have the same bit pattern, BUT in different number systems the bit pattern can be used to represent the two numbers as the different number systems cannot represent BOTH -32678 and +32768.