x = 0 and y = 4
Presumably this is a quadratic equation question in the form of: 9x2-12x+4 = 0 When factored: (3x-2)(3x-2) = 0 Solution: x = 2/3 and also x = 2/3 (they both have equal roots)
Yes, a linear equation in t.
If you start with the following equation of an ellipse: x2/4 + y2/9 = c2 and transform the equation to 9x2/36 + 4y2/36 = 36c2 the denominators are the same but the equation is unchanged and so the ellipse remains exactly as it was before.
This is a linear equation. The value x = -1 is the solution to this equation.
(3x+4)(3x-4)=0 x=±4/3
x = 4
-8
The range is {-5, -2, 1, 4}
It is: 122-4*(9*-2) = 216
This is the equation of a line with slope -4 and y intercept at 0. The domain is all real numbers as is the range.
9x2 + 4y = 36∴ 4y = 36 - 9x2∴ y = 9 - 9x2/4also:∴ 9x2 = 36 - 4y∴ x2 = 4 - 4y/9∴ x = (4 - 4y/9)1/2This equation represents a parabolic curve, so we know it will intercept the y-axis at one point, and the x-axis at either zero or two points. Let's start with the x-axis:y = 9 - 9x2/4Let y = 0:∴ 0 = 9 - 9x2/4∴ 0 = 36 - 9x2∴ 9x2 = 36∴ x2 = 4∴ x = +/- 2So the curve intercepts the x axis at the points -2, 0 and 2, 0As for the y axis:x = (4 - 4y/9)1/2Let x = 0:∴ 0 = (4 - 4y/9)1/2∴ 0 = 4 - 4y/9∴ 0 = 45 - 4y∴ 4y = 45∴ y = 45/4 = 11 1/4So the curve intercepts the y axis at the point 0, 11.25
9x2 - 12x + 4 = 0 is of the form ax2 + bx + c = 0 where the discriminant, D, can be found by D = b2 - 4ac First, you find the values of a, b and c: a = 9 b = -12 c = 4 Now you can find D: D = (-12)2 - (4)(9) = 144 - 36 = 108 D = 108
An equation.
2n+4=66
x = 0 and y = 4
-2