Are you asking how to solve for x if those two expressions equal each other?
-3x2 - 5x + 1 = 8x2 - 2x - 9
11x2 + 3x - 10 = 0
11x2 + 3x = 10
x2 + 3x/11 = 10/11
x2 + 3x/11 + (3/22)2 = 10/11 + (3/22)2
(x + 3/22)2 = 440/484 + 9/484
x + 3/22 = ± √(449 / 484)
x = 3/22 ± √449 / 22
x = (3 ± √449) / 22
Are you asking to find the derivatives of each expression?
if f(x) = -3x2 - 5x + 1
f'(x) = -6x - 5
if f(x) = 8x2 - 2x - 9
f'(x) = 16x - 2
Are you looking for their indefinite integrals?
∫(-3x2 - 5x + 1)dx = -x3 - 5x2/2 + x + C
∫(8x2 - 2x - 9)dx = 8x3/3 - x2 - 9x + C
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3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
if you meant: (-3)x²-5x+1=8x²-2x-9x=(±√(449)-3)/22 ≈ -0.1363636363636 ± 1.9263291000379x1=(√(449)-3)/22 ≈ 0.8268009136553x2=(-√(449)-3)/22 ≈ -1.0995281863826
2x plus 5x simplified is 7x.
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