Are you asking how to solve for x if those two expressions equal each other?
-3x2 - 5x + 1 = 8x2 - 2x - 9
11x2 + 3x - 10 = 0
11x2 + 3x = 10
x2 + 3x/11 = 10/11
x2 + 3x/11 + (3/22)2 = 10/11 + (3/22)2
(x + 3/22)2 = 440/484 + 9/484
x + 3/22 = ± √(449 / 484)
x = 3/22 ± √449 / 22
x = (3 ± √449) / 22
Are you asking to find the derivatives of each expression?
if f(x) = -3x2 - 5x + 1
f'(x) = -6x - 5
if f(x) = 8x2 - 2x - 9
f'(x) = 16x - 2
Are you looking for their indefinite integrals?
∫(-3x2 - 5x + 1)dx = -x3 - 5x2/2 + x + C
∫(8x2 - 2x - 9)dx = 8x3/3 - x2 - 9x + C
3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
if you meant: (-3)x²-5x+1=8x²-2x-9x=(±√(449)-3)/22 ≈ -0.1363636363636 ± 1.9263291000379x1=(√(449)-3)/22 ≈ 0.8268009136553x2=(-√(449)-3)/22 ≈ -1.0995281863826
5x + x = 5x Squared (5x^2) x + x equals 2 x's = 2 = squared - very simple & logic. no its not simple and logic 5x^2 is the result of 5x times x. 5x plus x is 6x. Think of the x as 1x not x so 1x + 5x= 6x. That's simple and logic.
2x plus 5x simplified is 7x.
3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
What is the result of adding -3x²-5x +1 and 8x²-2x-9?
4x2 -x -1 :D
If you meant 3x2 - 5x + 2, here is your answer 3x2 - 5x +2 = 0 => 3x2 - 3x - 2x + 2 = 0 => 3x(x-1) - 2(x-1) = 0 => (3x - 2) (x-1) = 0 => x = 2/3 or, x = 1
The quotient is: x^2 +2x +3
(3x2 + 2x + 1)
21x3-35x2+14x = 7x(3x2-5x+2)
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
3x2 - 5x - 2 can be factored into (3x + 1) (x - 2)
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.