Un = 4n - 13.
4
The rule is 5 10 15 20 25 30 .... etc and accordingly the next number in the sequence will be 106
The nth term of the sequence is 2n + 1.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The rule that generates the sequence is Un = 9 + 2n (for n = 1, 2, ...
I assume that would refer to the sequence of square numbers:1, 4, 9, 16, 25, etc. To generate the sequence, you can square each number: 1 squared, 2 squared, etc.
Un = 4n - 13.
1 2 3 4 5 2 5 8 11 14 ... If this is the sequence, the position-to-term rule is 3n-1. However, it could be another sequence depending on the rest of the terms.
The rule for the sequence is an = xn-1 + xn-2The sequence of numbers, 1, 1, 2, 3, 5, 8, 13, . . . , in which each successive number is equal to the sum of the two preceding numbers.
the rule is:keep adding double starting from 1
If the rule is Un = -10*11(4-n) for n = 1, 2, 3, 4 then you are nearly correct. Is is -10. Unfortunately, it is possible to fit other rules. For example: Vn = (-550,00n2 + 2,860,000n - 3,641,000)/100 for n = 1, 2, 3 generates the same sequence. This time, though, the next term is -10010.
It all depends on the sequence you are talking about. For example, the next number in the sequence 0,1,1,2,3,5,8,13,_ would be 21. This would be the Fibonacci sequence as the rule is add the 2 previous terms to get the next term. Another example would be this: 11,121,1331,14641,______.The missing number is 161051, following the pattern of powers of 11, 11^1, 11^2, 11^3 and so on. If you understand what I am trying to say, it all depends on the sequence you are trying to find the number in.
1, 4, 7, 10, 13, …
26073.
The nth term of an arithmetic sequence = a + [(n - 1) X d]
94-1-6-11