2x + 3y = 6 can be written in the standard slope-intercept form of y= mx + c, where 'm' is the slope.
3y = -2x + 6
y = -⅔x + 2
The slope of this linear graph is -⅔.
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6x+3y = -9 3y = -6x-9 y = -2x-3 Therefore the perpendicular slope is 1/2
2x + 3y = 12 y = -2/3 y + 4 slope is -2/3
Solve for y.2x - 3y = 52x - 2x - 3y = -2x + 5-3y = -2x + 5-3y/-3 = -2x/-3 + 5/-3y = (2/3)x - 3/5Clearly you see that the slope is 2/3.
Put in function, Y = mX + C, form. 6X + 3Y = - 9 3Y = - 6X - 9 Y = - 2X - 3 -------------------- m(slope) = - 2 ----------------------
2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3